A particle with charge
and mass
, moving under the influence of a uniform electric field
and a uniform magnetic field Bk, follows a trajectory from P to Q as shown. The velocities at P and Q are Vi and
. Choose the wrong statement.
Text Solution
Verified by ExpertsThe correct answer is:
C
, , , in going from P to Q increase in kinetic energy
work done by electric field.
or
or 
The rate of work done by E at
force due to
velocity.

At
is perpendicular to
and
, and no work is done by either field
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
An electric motor operating on a 60 Vdc supply draws a current of 10 A. If the efficiency of the mo…
A thin semicircular conducting ring of the radius is falling with its plane vertical in a horizont…
At a place the value of horizontal component of the earth's magnetic field is Weber . A metallic…
A circular loop of radius carrying current I lies in plane with its centre at origin. The total m…
Two identical circular loops of metal wire are lying on a table without touching each other. Loop-A…
A small square loop of wire of side l is placed inside a large square loop of wire of side . The l…